Tardigrade Tardigrade - CET NEET JEE Exam App
- Tardigrade
- Question
- Chemistry
- C6H5NH2 ->[NaNO2/HCI][0°C] X ->[CuCN] Y ->[H2O/H][] Z, Z is identified as
8384 191 VITEEEVITEEE 2013 Report Error
Solution:
Correct answer is (d)
8384 191 VITEEEVITEEE 2013 Report Error
Solution: